There are 2 rounds:
1. Online Written Test
2. Interview (Technical & HR Interview)
The written test contained following sections
1.Quantitative Aptitude (25 Ques-35Mins)
2.Reasoning Questions (25 Ques-34Mins)
3.Verbal (25 Ques-25Mins)
Written Test
Coming about the written test it is online. But u should be careful here because there is no option of going back to previous questions. Also u cannot go to next question without answering the current question. So the bits should be answered sequentially.
The written test was extremely easy and simple (mainly quant). It included al 8th,9th10th class questions................here are some of ques which I remembered
Quantitative Aptitude
1.What is the value of log(-9)
(a) 1/3 (b)-3 (c)1/9 (d)undefined ans:(d)
2.find x if log√x27 = 6
(a)2 (b)3 (c)27 (d)1/3 ans:(b)
3.how many 4 digit numbers are possible using digits 1,2,3,4,5 without repetition of digits such that these numbers are divisible by 4
(a)21 (b)22 (c) 18 (d)24 ans: (d)
4.The h.c.f and l.c.m of 2 numbers is same. Their product is 729.then the number is:
(a) 21 (b) 9 (c)27 (d)12 ans:(c)
5. x=1+21/2,y=1-21/2 then what is x2+y2
(a)6 (b)4 (c)8 (d)none ans:(a)
HCL PAPER ON 26th NOVEMBER AT CHENNAI
Hi... Friends Bhaskar reddy here.. I was attended for HCL Technologies in Anna University on nov 26th and I got placed. Here I am presenting my experience in written test and interview. I hope it may be useful for you…
Written test consists of 4 sections. In each section we have to get minimum marks. Which means it’s a sectional cut off. Also negative marking is there. They will deduct ¼ of each wrong answer... Ok... You just answer all questions with lot of confidence...ok
They will give all 4 sections question paper at a time… so you can start any section.
Total paper consists of 65 Questions and provided 90 mini times. So that you can answer each and every section very carefully… ok
SECTION-I :( Microprocessor (8086only) +Networks+operatingsystems+Fundamentals of computers)
This section consists of 15 Questions. Here I remember some questions……
1) Non Maskable Interrupt is a…..
a) NMI
b) Software interrupts
c) Hardware interrupts
d) Software and hardware interrupt
Ans: b
2) Which of the following is error correction and deduction?
a) Hamming code
b) CRC
c) VRC
d) None
Ans: b
3) When you switch on your computer, which of the following component affect first?
a) Mother board
b) SMPS
c) Peripherals
d) None
Ans : a
4) Which of the following function transports the data?
a) TCP/IP
b) Transport layer
c) TCP
d) None
Ans: c
5) Which of the following does not consists address?
a) IP
b) TCP/IP
c) Network
d) Transport
Ans:a
6) They given like this……. And some conditions?
a) pre order
b) post order
c) In order
d) None
Ans:c
7) Authentication means….
a) Verifying authority
b) Source
c) Destination
d) Request
Ans: a
8) Symorphous is used for
a) Analysis
b) Synchournization
c) Asynchrouns
d) None
Ans: b
9) There are five nodes. With that how many trees we can make?
a) 27
b) 28
c) 30
d) 29
Ans: c (Check the ans not sure)
10) Traverse the given tree using in order, Preorder and Post order traversals.
A
B
C
D
E
F
G
H
I
Given tree:
Ø Inorder : D H B E A F C I G J
Ø Preorder: A B D H E C F G I J
Ø Postorder: H D E B F I J G C A
And some more questions….. I dint remember those questions
Given tree:
Ø Inorder : D H B E A F C I G J
Ø Preorder: A B D H E C F G I J
Ø Postorder: H D E B F I J G C A
And some more questions….. I dint remember those questions
SECTION –II (C language Basics and programming) this section consists of 20 Questions…….. All are programs only…
1. main()
{
printf("%x",-1<<4);
}
a) fff0
b) fffb
c) ff0
d) none
Ans: a
Explanation:
-1 is internally represented as all 1's. When left shifted four times the least significant 4 bits are filled with 0's.The %x format
specifier specifies that the integer value be printed as a hexadecimal value.
2. main()
{
char *p;
p="Hello";
printf("%c\n",*&*p);
}
a) e
b) H
c) some address
d) ome garbage value
Ans: b
Explanation:
* is a dereference operator & is a reference operator. They can be applied any number of times provided it is meaningful. Here
p points to the first character in the string "Hello". *p dereferences it and so its value is H. Again & references it to an address and * dereferences it to the value H.
3. void main()
{
int i=5;
printf("%d",i++ + ++i);
}
a) 11
b) 12
c) 10
d) output cant be predicted
Ans: d
Explanation: Side effects are involved in the evaluation of i
4. main( )
{
int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1);
}
a) 100, 100, 100, 2
b) 101,101,101,2
c) 114,104,102,3
d) none
Ans: c
Explanation:The given array is a 3-D one. It can also be viewed as a 1-D array.
2 4 7 8 3 4 2 2 2 3 3 4
100 102 104 106 108 110 112 114 116 118 120 122
thus, for the first printf statement a, *a, **a give address of first element . since the indirection ***a gives the value. Hence, the first line of the output.for the second printf a+1 increases in the third dimension thus points to value at 114, *a+1 increments in second dimension thus points to 104, **a +1 increments the first dimension thus points to 102 and ***a+1 first gets the value at first location and then increments it by 1. Hence, the output is C is correct answer…
5. main( )
{
static int a[ ] = {0,1,2,3,4};
int *p[ ] = {a,a+1,a+2,a+3,a+4};
int **ptr = p;
ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*++ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
++*ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
}
a) 111
222
332
443
b) 111
222
333
344
c) 111
222
333
444
d) None
Ans: b
6. #include
main()
{
const int i=4;
float j;
j = ++i;
printf("%d %f", i,++j);
}
a) 8
b) 5
c) compile error
d) syntax error
Ans: c
7. main()
{
char *p;
int *q;
long *r;
p=q=r=0;
p++;
q++;
r++;
printf("%p...%p...%p",p,q,r);
}
a) 001… 100…0002
b) 0001...0002...0004
c) 001… 002…004
d) none
ans: b
8. main()
{
unsigned int i;
for(i=1;i>-2;i--)
printf("HCL Technologies");
}
a) HCL
b) Technologies
c) HCL Technologies
d) None
Ans: None(Plz Check the answer)
9. main()
{
int a[10];
printf("%d",*a+1-*a+3);
}
a) 4
b) 5
c) 6
d) None
Ans : a
10. main()
{
float f=5,g=10;
enum{i=10,j=20,k=50};
printf("%d\n",++k);
printf("%f\n",f<<2);
printf("%lf\n",f%g);
printf("%lf\n",fmod(f,g));
}
a) Line no 5: Error: Lvalue required
b) Line no 5: Error: Link error
c) Compile error
d) None
Ans: a
11. int swap(int *a,int *b)
{
*a=*a+*b;*b=*a-*b;*a=*a-*b;
}
main()
{
int x=10,y=20;
swap(&x,&y);
printf("x= %d y = %d\n",x,y)
}
a) x=10 y=20
b) x=20 y=10
c) x=30 y=20
d) none
Ans: b
12. main()
{
int i=300;
char *ptr = &i;
*++ptr=2;
printf("%d",i);
}
a) 665
b) 565
c) 556
d) none
Ans: c
13.main()
{
float me=1.1;
double you=1.1;
if(me==you)
printf(”IloveU”);
else
printf(“I Hate U”)
}
a) I love u
b) I hate u
c) floating point error
d) Compile error
Ans: b
14.
enum colors {BLACK,BLUE,GREEN}
main()
{
printf(”%d..%d..%d”,BLACK,BLUE,GREEN);
return(1);
}
a) 1..2..3
b) 0..1..2
c) 2..3..4
d) none
Ans: b
Some more questions given.. I dint remember…. Be prepare all basic concept in C… so that you can answer very easily…
SECTION –III (Data structures and C++) this section consists of 10 Questions… Each question carry 2 marks… so they deduct ½ mark for wrong answer…..
1) #include
main()
{
char s[]={'a','b','c','\n','c','\0'};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}
a)97
b) M
c)76
d) none
Ans: b
2) main( )
{
int a[ ] = {10,20,30,40,50},j,*p;
for(j=0; j<5; j++)
{
printf(“%d” ,*a);
a++;
}
p = a;
for(j=0; j<5; j++)
{
printf(“%d ” ,*p);
p++;
}
}
a) address of array
b) Compile error
c) Lvalue required
d) none
Ans: c
3) struct aaa{
struct aaa *prev;
int i;
struct aaa *next;
};
main()
{
struct aaa abc,def,ghi,jkl;
int x=100;
abc.i=0;abc.prev=&jkl;
abc.next=&def;
def.i=1;def.prev=&abc;def.next=&ghi;
ghi.i=2;ghi.prev=&def;
ghi.next=&jkl;
jkl.i=3;jkl.prev=&ghi;jkl.next=&abc;
x=abc.next->next->prev->next->i;
printf("%d",x);
}
a) 3
b) 2
c) 4
d) 5
Ans: b
4) main(int argc, char **argv)
{
printf("enter the character");
getchar();
sum(argv[1],argv[2]);
}
sum(num1,num2)
int num1,num2;
{
return num1+num2;
}
a) compile error
b) L value required
c) Syntax error
d) None
Ans: a
5)
class Sample
{
public:
int *ptr;
Sample(int i)
{
ptr = new int(i);
}
~Sample()
{
delete ptr;
}
void PrintVal()
{
cout << "The value is " << *ptr;
}
};
void SomeFunc(Sample x)
{
cout << "Say i am in someFunc " << endl;
}
int main()
{
Sample s1= 10;
SomeFunc(s1);
s1.PrintVal();
}
a) say I am in someFunc
b) say I am in someFunc and runtime error
c) say I am in someFunc and null value
d) none
ans: b
and some questions given in DATASTURES… those are based on linked lists only also very big programs… so you have to do it very careful
SECTION-III (General aptitude+1 passage+Logical) this section consists of 20 questions.. Each question carry 1 mark…
1) Sandhya and Bhagya is having the total amount of 12000. In that amount bhagya has deducted 3600 as less as sandhya. So what is their shared amount?
a) 2800
b) 3600
c) 4800
d) 9600
Ans : c
2) Six persons have to present at certain meeting. The conditions are,
A present P should present
M present T should present
K present P should present
If A and P present I should be there in meeting
If M and T present D should be absent
If K and P present P should present
Based on this they given some questions… Those are easy only.. you can do it easily…
3) Here they given passage following some questions.. Poetry explaining her experience with HINDI latest songs… and comparing with old songs… also she is a good singer. Like this they given a big passage… so read it carefully at a time.. so that u can save your time
4) Dhana and Lavanya started running at same point… But dhana started in anti clock wise direction, Lavanya started in clockwise direction.. Dhana met lavanya at 900 m . where as lavanya met dhana at 800 m… so how much distance they covered each other?
a) 1700
b) 900
c) 1800
d) data is insufficient
Ans: d
5) This question is base on Arithmetic mean like algebra… a n+2 = (7+an)/5…. Initially a0= 0…… so what is the value of a2?
a) 5/2
b) 7/2
c) 7/5
d) none
Ans : c
6) Here they given two statements, based on that they gave some questions
Statement I : I is enough to answer
Statement II: I and II is enough to answer
i) Raja can do a piece of work in 9 days… and govardhan can do a piece of work in 8 days. In how many days they will complete the work alternatively..
Statement I: They both do in 72/17 days
Statement II : A alone can do 1/9 days
a) I b) I and II c) II d) none
Like this they given some questions……
Hi...my Technical interview held like this..
Intwr: Hi, I am Mahesh butt
Me: hi sir I am bhaskarreddy
Intwr: ok.. Which project u did in your curriculum?
Me: sir my project is steganography
Intwr: oh... What is steganography?Why you choose this project? What’s your project purpose?
What is encryption?How you embedded the selection of sector? Which code u used?Which algorithm you used? Can you explain me?
Mostly I answered all questions.. Also he gave me paper and pen... Like that I explained to him very clearly with diagrams.
Intwr: So bhaskar u knows C well? You are good at C language?
(Because I wrote C and .NET in my resume)
Me: no... Sir, I am not proficient in C, but logically I am good and I am in intermediate stage.
Intwr: oh..ok… What is your area of interest?
Me: Digital Electronics… sir
Intwr: Are you sure?
Me: yes sir…(With lot of confidence)
Intwr:
A0
B0
\
c=1
A1
B1
Bhaskar you use your entire Digital electronics, but I Want inside circuit which always shows the output as 1.
The conditions are,
When x=0: AWhen x=1: A>B When condition is false , output is 0
Consider A=A0A1
Consider B= B0B1
Here he given the time of 15 mini to solve above problem…. But I did it with in 5 mini with logic gates.
Then he asked me to explain the entire circuit?
I explained to him……….
Ok.. Bhaskar I am giving one more 15 mini time to solve above question…. But this time you have to do with Multiplexers….
Yes.. here I designed the circuit and I explained to him…. Here I impressed him a lot..
Intwr: Ok.. Good…. Draw the block diagram of Feed back amplifier?
Me: I drawn the diagram
Intwr: You just add forward and reverse bias diodes to the feedback? I did it… ok.. will this circuit runs
Me: Yes…. Sir
Intwr: why
Me: No sir
Intwr: why
Me: Bcz some nose occurs in output and said some thing..
Intwr: What is pointer?
What is data sturucture?
What is stack?Queue?
Explain the Doubly linked list program?
I explained to him very clearly…
Intwr:
main()
{
int *j;
{
int i=10;
j=&i;
}
printf("%d",*j);
printf(“%d”, j);
}
What is the output?
Me: I did it correctly
Intrwr: Write a program for Fibonacci series? But I want to print only last value?
Me: I wrote program for Fibonacci series.. But I don’t know how to print last value…
Intwr: are you shivering
Me: yes... Sir...
Intwr: why bhaskar.. You are good at your subject why cant you do this???
Me: I tried it.. at last I got it
Intwr: Ok bhaskar.. Now you can go…….
Me: Sir... Am I fit for HCL?
Intwr: Bhaskar lets see your dreams comes true
Me: Thank you sir…
After some time they called me to HR round.. That time only I decided that I cleared technical round..
HR: Hi... I am priya
Me: I am Bhaskar Reddy
HR: Tell me some thing about you?
Why you joined in Bhajarang?
In which domain you will work?
And some more simple questions?
Paper pattern
1) In a murder case there are four suspects P,Q,R,S. Each of them makes a statement. They are p: "I had gone to the theatre with S at the time of the murder". q: "I was playing cards with P at the time of the murder". r: "Q didn't commit the murder". s: "R is not the murderer".
Assuming the only one of the above statement is false and that one of them is the murderer, who is the murderer?
a) P
b) Q
c) R
d) Cann't be concluded
e) S
and: E.) r and s are true as first two statements are contradictory. thus either P or S is murederer. as q is not murderer, he is tellinjg truth that P was with him. hence S is murderer.
2) Mohan earned twice as much as Deep. Yogesh earned rs.3/- more than half as much as deep. If the amounts earned by Mohan,Deep,Yogesh are M,D,Y respectively, Which of the following is the correct ordering of these amounts?
a) M < D < Y
b) M < Y < D
c) D < M < Y
d) It cann't be determined from the information given
e) D < Y < M
ans d)
03) Statistics indicate that men drivers are involved in more accidents than women drivers.
Hence it may be concluded that...
a) sufficiently information is not there to conclude anything
b) Men are actually better drivers but drive more frequently
c) Women Certainly drive more cautiously than Men
d) Men chauvinists are wrong about women's abilties.
e) Statistics sometimes present a wrong picture of things
04) What does the hex number E78 correspond to in radix 7 ?
a) 12455
b) 14153
c) 14256
d) 13541
e) 13112
Ans: d
5)Given that A,B,C,D,E each represent one of the digits between 1 and 9 and that the following multiplication holds:
A B C D E
X 4
E D C B A
what digit does E represent ?
a) 4
b) 6
c) 8
d) 7
Ans: c
6) HCL prototyping machine can make 10 copies every 4 seconds. At this rate, How many copies can the machine make in 6 min.?
a) 900
b) 600
c) 360
d) 240
e) 150
Ans: a
7) if a=2,b=4,c=5 then a+b c c a+b
a) 1
b) 11/30
c) 0
d) -11/30
e) -1
Ans: b
8) 10^2(10^8+10^8) = 10^4
a) 2(10)^4
b) 2(10)^6
c) 10^8
d) 2(10)^8
e) 10^10
Ans: b
9) Worker W produces n units in 5 hours. Workers V and W, workers independently but at the same time, produce n units in 2 hours. how long would it take V alone to produce n units?
a) 1 hr 26 min
b) 1 hr 53 min
c) 2 hr 30 min
d) 3 hr 30 min
e) 3 hr 20 min
Ans: d (e)
11-15 is the reasoning Questions: Occurs and Causes available in placement papers.com
Six knights - P,Q,R,S,T and U - assemble for a long journey in two travelling parties. For security, each travelling party consists of at least two knights. The two parties travel by separate routes, northern and southern. After one month, the routes of the northern and southern groups converge for a brief time and at that point he knights can, if they wish, rearrange their travelling parties before continuing, again in two parties along separate northern and southern routes. Throughout the entire trip, the composition of travelling parties must be in accord with the following conditions
P and R are deadly enemies and, although they may meet briefly, can never travel together.
p must travel in the same party with s
Q cann't travel by the southern route
U cann't change routes
16) If one of the two parties of knights consists of P and U and two other knights and travels by the southern route, the other members of this party besides P and U must be.
a) Q and S
b) Q and T
c) R and S
d) R and T
e) S and T
Ans: e
17) If each of the two parties of knights consists of exactly three members, which of the following is not a possible travelling party and route?
a) P,S,U by the northern route
b) P,S,T by the northern route
c) P,S,T by the southern route
d) P,S,U by the southern route
e) Q,R,T by the southern route
Ans: b
18) If one of the two parties of knights consists of U and two other knights and travels by the northern route, the other memnbers of this party besides U must be
a) P and S
b) P and T
c) Q and R
d) Q and T
e) R and T
Ans: c
19) If each of the two parties of knights consists of exactly three members of different pX-Mozilla-Status: 0009by the northern route, then T must travel by the
a) southern route with P and S
b) southern route with Q and R
c) southern route with R and U
d) northern route with Q and R
e) northern route with R and U
Ans: a
20) If, when the two parties of knights encounter one another after a month, exactly one knight changes from one travelling party to the other travelling party, that knight must be
a) P
b) Q
c) R
d) S
e) T
Ans: e
APTITUDE PAPER
1 The closing of the resturant by Mr.X on SEPT 1 was considered an unfinancial one, as the weather remained unusually
clear and sunny for another one month. An author who criticizes the act of Mr. X would be proved wrong if the
following was true?? ANS choice a) the weather did not usually remained fine after SEPT 1.
2 SUSAN works in a company who has restricted its employees from smoking cigerrates in the canteen. As susan
is the employee of the company she does not smoke cigerrate in the canteen.Which of the following unused
phrases strengthens the rules of the company?? ANS the employees normally do not do the work for which the
company has forbidden them to do.
3 A q's on family relation was given like How many sons X has, I P is the daughter of X ,II some condt., III some
condt. ANS al I ,II, III together are not sufficient.
4 A q's in which a name KAPIL is given he visits manoj's home.some condts given. ANS b)
5 A,B,C,D are the 4 plays which are organised starting from tuesday.find the day on which C was played.in this
2 condt. will be given as , I.....................,
II...................., ANS both I and II
6 A quest on crypto graphy like
A B C D
E F G H
--------------
. .................... .is A=, find the other values. practice these types of quest.
7. A question on race was given.hell lot of condts. finally they make a team for 4*100 metres medaly.
ANS E none of the above
8. Piggy backing is a technique for a) Flow control b) sequence c) Acknowledgement d) retransmition
ans: c piggy backing
9.. The layer in the OST model handles terminal emulation
a) session b) application c) presentation d) transport
ans: b application
10 ans: a odd numbers of errors
11. In signed magnitude notation what is the minimum
value that can be represented with 8 bits
a) -128 b) -255 c) -127 d) 0 ANS a)
12 c 20(no of address lines in 1MB of memory)
13 A 120(25 hz processor,what is the time taken by the instr which needs 3 clock cycles)
14 B synchronise the access(semaphores used for)
15 A system call(context switching is used in)
16 B the operating system(mapping of virtual to physical address)
17 A 177333(conversion of HEX "0xFEDB"in octal)
18 D used as a network layer protocall in network and windows(OLE) system
19 B has to be unique in the sub network(internet address)
20. There is an employer table with key feilds as employer no. data in every n'th row are needed for a simple
following queries will get required results.
a) select A employe no. from employe A , where exists
from employe B where A employe no. >= B employe
having (count(*) mod n)=0
b) select employe no. from employe A, employe B where
A employe no. >= B employ no. grouply employe no.
having (count(*) mod n=0 )
c) both a& b d)none of the above
21 . type duplicates of a row in a table customer with non uniform key feild customer no. you can see
a) delete from costomer where customer no. exists ( select distinct customer no. from customer having count )
b) delete customer a where customer no. in (select customer b where custermer no. equal to b custemor no.)
and a rowid > b rowid c) delete customer a where custermor no. in ( select customer no. from customer a,
customer b ) d) none of the above
22. which feature in ANSI C but not in JAVA.??ANS variable arguments.
23. preprocessor does not do one of the following??ANS type checking.
24. long int size a) 4 bytes b) 2 bytes c) compiler dependent d) 8 bytes
ans: compiler dependent
25. x=2,y=6,z=6 x=y==z;
printf(%d",x) ?ANS 1
26. class c : public A,publicB
a) 2 members in class a,b can have member functions with same name.
b) 2 members in class a,c can have member functions
with same name. c)both d)none(ANS)
27. What will be the out put of the following program
main()
{
char *p;
p=malloc(10);
free(p);
printf("%d",p);
}
ANS compilation error
28. a=(10,15), b=10,15 what are the values of a & b in ANSI C ANS 15,10
29 main()
{
int x=10,y=15,z=16;
x=y=z;
printf("%d",x);
}
ANS 0
30 f(n) f(x)
{
if(x<=0)
return;
else f(x-1)+x;
}
find the value of fn(5)? ANS 15.
31 struct {
int det;
struct prevoius;
struct new;
}
delete(struct node)
{
node-prev-next=node-next;
node-next-prev=node-prev;
if(node==head)node
}
one element will be given. ANS::it
does not work when rp is the last element in the link list.
32 A code will be given which searches a particular char in the string. ANS:: it always works.
33. main()
{
int var =25,varp;
varp=&var;
varp p=10;
fnc(varp);
printf("%d%d",var,varp);
}
ANS::55,55 (check this out)
34. #define VALUE 1+2
main()
{
printf("%d and %d\n",VALUE/VALUE,VALUE*3);
}
ANS:: 5,7
35 What is the value assigned to the variable a if b is 7 a=b>8?b<<2:b>4?b>>1:b; ANS::3
36 .the value of the following expr (2^3)+(a^a) is a) 1 b)2 c) 3 d) insufficient data
37 which of the following is not basic data type ANS char*
38. the declaration of the variable does not result in oneof the following ANS allocatrion of the storage space for the
varable.
39. in C parameters are passed by ANS:: value only.
40. 2 variables cannot have the same name if they are ANS:: in the same block.
41.a static funct. say s(),in as file f.c can be invoked from ANS all functs. in f.c after the definitions of s.
42.macros and functions do not differ in the following aspects ANS::variable no of arguments.
43.one q's in which he will give some different forms of STRCPY function you will have to find out which form is
correct.
So after that she gave me offer letter… so that was the great exciting moment in my life…
So friends don’t ever loose your hopes.. Keep on trying.. Surely one good day is waiting for you.. Till then you do hard work… ok.. Hard work never fails… GOOD LUCK
ALL THE BEST FOR YOUR FUTURE
